A) \[\frac{{{I}_{0}}}{4}\]
B) \[\frac{3{{I}_{0}}}{4}\]
C) \[\frac{3{{I}_{0}}}{8}\]
D) \[\frac{{{I}_{0}}}{8}\]
Correct Answer: D
Solution :
\[{{I}_{1}}=\frac{{{I}_{0}}}{2}\] \[I={{I}_{1}}{{\cos }^{2}}\theta \] \[=\frac{{{I}_{0}}}{2}{{\cos }^{2}}({{90}^{o}}-{{30}^{o}})\] \[=\frac{{{I}_{0}}}{2}{{\cos }^{2}}{{60}^{o}}=\frac{{{I}_{0}}}{2}\times {{\left( \frac{1}{2} \right)}^{2}}\] \[=\frac{{{I}_{0}}}{2}\times \frac{1}{4}=\frac{{{I}_{0}}}{8}\]
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