A) 2H
B) 5H
C) 10 H
D) 20 H
Correct Answer: B
Solution :
\[U=\frac{1}{2}L{{I}^{2}}\] \[\therefore \] \[P=\frac{dU}{dt}\] Or \[P=\frac{1}{2}\times L\times (2I)\frac{dI}{dt}\] Or \[P=LI\frac{dI}{dt}\Rightarrow L=\frac{P}{I\left( \frac{dI}{dt} \right)}\] Or \[L=\frac{0.5}{0.2\times (0.5)}=5H\]You need to login to perform this action.
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