A) 1: 2
B) 1 : 1
C) 3 : 1
D) 2 : 1
Correct Answer: D
Solution :
\[{{E}_{1}}+{{E}_{2}}=k\times 6\] ?..(i) \[{{E}_{1}}-{{E}_{2}}=k\times 2\] ...(ii) Solving Eqs. (i) and (ii), we get \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{2}{1}\] \[\Rightarrow \] \[{{E}_{1}}:{{E}_{2}}=2:1\]You need to login to perform this action.
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