A) \[0.453\times {{10}^{-10}}\]
B) \[0.530\times {{10}^{-10}}\]
C) \[1.12\times {{10}^{-10}}\]
D) \[2.12\times {{10}^{-10}}\]
Correct Answer: C
Solution :
\[AgCl\underset{S}{\mathop{A{{g}^{+}}}}\,+\underset{S}{\mathop{C{{l}^{-}}}}\,\] \[[A{{g}^{+}}]=[C{{l}^{-}}]=1.06\times {{10}^{-5}}g\,ion/L\] \[{{K}_{sp}}=[A{{g}^{+}}][C{{l}^{-}}]={{S}^{2}}\] \[={{(1.06\times {{10}^{-5}})}^{2}}=1.12\times {{10}^{-10}}\]
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