MGIMS WARDHA MGIMS WARDHA Solved Paper-2009

  • question_answer
    A radioactive substance decays to,\[\frac{3}{4}\]th of its original value in 2h. The half-me of the substance is

    A)  1 h                                        

    B)  30 min

    C)  1 h 30 min          

    D)  None of these

    Correct Answer: A

    Solution :

                     \[k=\frac{2.303}{t}\log \frac{{{N}_{0}}}{N}\] \[=\frac{2.303}{t}\log \frac{1}{1-\frac{3}{4}}\] \[=\frac{2.303}{2}\log 4=0.693\,{{h}^{-1}}\] \[{{t}_{1/2}}=\frac{0.693}{k}=\frac{0.693}{0.693}=1\,h\]


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