A) 2
B) 4
C) 8
D) 10
Correct Answer: B
Solution :
The possible structural isomers of\[{{C}_{4}}{{H}_{9}}Cl\]are (i)\[\underset{1-chloro\text{ }bu\tan e}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}Cl}}\,\] (ii) \[\underset{2-chloro\text{ }butane}{\mathop{C{{H}_{3}}C{{H}_{2}}\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{CH}}\,C{{H}_{3}}}}\,\] (iii) \[\underset{1-chloro-2-r,thylpropane}{\mathop{C{{H}_{3}}\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,C{{H}_{3}}}}\,-Cl\] (iv) \[\underset{2-chloro-2-meayl\text{ }propane}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} Cl \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{3}}}}\,\]
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