A) 0.1%
B) 0.2%
C) 0.3%
D) 0.4%
Correct Answer: D
Solution :
Moment of inertia \[(I)=\frac{2}{5}M{{R}^{2}}\] \[\Rightarrow \] \[\Delta I=\frac{2}{5}M2R\Delta R\] \[\therefore \] \[\frac{\Delta I}{I}=2\frac{\Delta R}{R}=2\alpha \Delta T\] \[\therefore \]Percentage increase in moment of inertia \[=2\alpha \Delta T\] \[=2\times {{10}^{-5}}\times 200\] \[=4\times {{10}^{-3}}=0.4%\]You need to login to perform this action.
You will be redirected in
3 sec