2. Solved Papers
  3. MGIMS WARDHA

MGIMS WARDHA MGIMS WARDHA Solved Paper-2009

  • question_answer
    Solution of\[0.1N{{H}_{4}}OH\]and\[0.1N\,N{{H}_{4}}Cl\]has pH 9.25. Then,\[p{{K}_{b}}\]of\[N{{H}_{4}}OH\]is

    A)  9.25                                      

    B)  4.75

    C)  3.75                                      

    D)  8.25

    Correct Answer: B

    Solution :

                     \[pOH=p{{K}_{b}}+\log \frac{[salt]}{[base]}\] \[\because \]     \[[N{{H}_{4}}Cl]=[N{{H}_{4}}OH]\] \[\therefore \]  \[pOH=p{{K}_{b}}\]                 \[p{{K}_{b}}=pOH=14-pH\]                 \[=14-9.25=4.75\]


You need to login to perform this action.
You will be redirected in 3 sec spinner