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MGIMS WARDHA MGIMS WARDHA Solved Paper-2010

  • question_answer
    A gaseous mixture contains\[56g{{N}_{3}},44gC{{O}_{2}}\] and\[16gC{{H}_{4}}\]. The total pressure of the mixture is 720 mm Hg. What is the partial pressure of\[C{{H}_{4}}\]?

    A)  142mm                               

    B)  156mm

    C)   182mm                              

    D)  180mm

    Correct Answer: D

    Solution :

                     \[56g{{N}_{2}}=\frac{58}{28}=2\,mol\] \[44gC{{O}_{2}}=\frac{44}{44}=1\,mol\] \[16gC{{H}_{4}}=\frac{16}{16}=1\,mol\] Partial pressure of \[C{{H}_{4}}\] \[=\frac{{{n}_{C{{H}_{4}}}}}{{{n}_{{{N}_{2}}}}+{{n}_{C{{O}_{2}}}}+{{n}_{C{{H}_{4}}}}}\times p\] \[=\frac{1}{2+1+1}\times 720=180\,mm\]            


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