A) 0.1 s
B) 0.01 s
C) 1 s
D) 10 s
Correct Answer: A
Solution :
Induced emf\[e=-\frac{\Delta \phi }{\Delta t}\] \[e=-\frac{({{\phi }_{2}}-{{\phi }_{1}})}{t}\] \[=-\frac{(0-nBA)}{t}=\frac{nBA}{t}\] \[\therefore \] \[0.1=\frac{50\times 2\times {{10}^{-2}}\times 100\times {{10}^{-4}}}{t}\] \[\Rightarrow \] \[t=\frac{50\times 2\times {{10}^{-2}}\times 100\times {{10}^{-4}}}{0.1}\] \[=0.1\,s\]You need to login to perform this action.
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