A) y = A sin \[(\omega t-kx)\]
B) y = - 0.8 A sin\[(\omega t-kx)\]
C) y = 0.8 A sin \[(\omega t+kx)\]
D) y = A sin \[(\omega t+0.8\,kx)\]
Correct Answer: B
Solution :
On getting reflected from a rigid boundary the wave suffers an additional phase change of\[\pi \] \[\Rightarrow \]\[y=0.8\,A\,\sin (\omega t+kx+\pi )\] \[\Rightarrow \]\[y=-0.8\,A\,\sin (\omega t+kx)\]You need to login to perform this action.
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