question_answer

A voltmeter of resistance 998\[\Omega \] is connected across a cell of emf 2 V and internal resistance 2\[\Omega .\]The potential difference across the voltmeter is

A)  1.99V                                   

B)  3.5 V

C)   5V                                        

D)  6V

Correct Answer: A

Solution :

                 From Ohm's law \[i=\frac{E}{R+r}=\frac{2}{998+2}\]                 \[=2\times {{10}^{-3}}A\] \[R=988\,\Omega \] Potential difference across the voltmeter is \[V=iR=(2\times {{10}^{-3}})\times 998=1.996\,V\]