MGIMS WARDHA MGIMS WARDHA Solved Paper-2010

  • question_answer
    The temperature at which the mean KE of the molecules of gas is one-third of the mean KE of its molecules at \[180{}^\circ C\] is

    A) \[-122{}^\circ C\]   

    B) \[-90{}^\circ C\]

    C) \[60{}^\circ C\]

    D) \[151{}^\circ C\]

    Correct Answer: A

    Solution :

    Kinetic energy of a gas is directly proportional to its temperature. \[\therefore \]  \[\frac{{{K}_{1}}}{{{K}_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\] \[\Rightarrow \]               \[\frac{k}{K/3}=\frac{273+180}{{{T}_{2}}}\] \[\Rightarrow \]              \[3=\frac{453}{{{T}_{2}}}\] \[{{T}_{2}}=151K=151-273=-{{122}^{o}}C\]


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