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MGIMS WARDHA MGIMS WARDHA Solved Paper-2010

  • question_answer
    If the binding energy of the electron in a hydrogen atom is 13.6 eV, the energy required to remove the electron from the first excited state of Li2+ is

    A)  30.6 eV                               

    B)  13.6 eV

    C)  3.4 eV                                 

    D)  122.4 eV

    Correct Answer: A

    Solution :

                     \[E=-{{Z}^{2}}\frac{13.6}{{{n}^{2}}}eV\] For first excited state \[{{E}_{2}}=-{{3}^{2}}\times \frac{13.6}{4}\] \[=-30.6eV\]Ionization energy for first excited state of\[L{{i}^{2+}}\] is 30.6 eV.


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