2. Solved Papers
  3. MGIMS WARDHA

MGIMS WARDHA MGIMS WARDHA Solved Paper-2010

  • question_answer
    If the electric fluxes entering and leaving an enclosed surface respectively are\[{{\phi }_{1}}\]and \[{{\phi }_{2,}}\] the electric charge inside the surface will be

    A) \[({{\phi }_{2}}-{{\phi }_{1}}){{\varepsilon }_{o}}\]                           

    B) \[({{\phi }_{1}}+{{\phi }_{2}})/{{\varepsilon }_{o}}\]

    C) \[({{\phi }_{2}}-{{\phi }_{1}})/{{\varepsilon }_{o}}\]                         

    D) \[({{\phi }_{1}}+{{\phi }_{2}})/{{\varepsilon }_{o}}\]

    Correct Answer: A

    Solution :

                     From Gauss's law, \[\frac{Charge\text{ }enclosed}{{{\varepsilon }_{0}}}=\] Flux leaving the surface \[\frac{q}{{{\varepsilon }_{0}}}={{\phi }_{2}}-{{\phi }_{1}}\] \[\Rightarrow \]               \[q=({{\phi }_{2}}-{{\phi }_{1}}){{\varepsilon }_{0}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner