A) glucose and fructose
B) glucose and lactose
C) glucose and galactose
D) only glucose
Correct Answer: A
Solution :
\[\underset{\begin{smallmatrix} sucorse \\ \\ {{[\alpha ]}_{D}}=+{{66.5}^{o}} \end{smallmatrix}}{\mathop{{{C}_{12}}{{H}_{22}}{{O}_{11}}}}\,+{{H}_{2}}O\xrightarrow{HCl}\underset{\begin{smallmatrix} D(+)glu\cos e \\ \\ {{[\alpha ]}_{D}}=+{{52.5}^{o}} \end{smallmatrix}}{\mathop{{{C}_{6}}{{H}_{12}}{{O}_{6}}}}\,\] \[+\underset{\begin{smallmatrix} D(-)fructose \\ {{[\alpha ]}_{D}}=-{{92.4}^{o}} \end{smallmatrix}}{\mathop{{{C}_{6}}{{H}_{12}}{{O}_{6}}}}\,\] Sucrose is dextrorotatory and the resulting solution is laevorotatory with specific rotation of\[-39.9{}^\circ \]because fructose has a greater specific rotation. Since, there is a change in sign from dextrorotatory to laevorotatory, the reaction is called inversion reaction and thus, sucrose (obtained from glucose and fructose) is called invert sugar.You need to login to perform this action.
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