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MGIMS WARDHA MGIMS WARDHA Solved Paper-2010

  • question_answer
    A wave travelling along positive \[x\]-axis is given by \[y\] = A sin \[(\omega t-kx).\] If it is reflected from rigid boundary such that 80% amplitude is reflected then equation of reflected wave is

    A)  y = A sin \[(\omega t-kx)\]  

    B)  y = - 0.8 A sin\[(\omega t-kx)\]

    C)   y = 0.8 A sin \[(\omega t+kx)\]

    D)  y = A sin \[(\omega t+0.8\,kx)\]

    Correct Answer: B

    Solution :

                     On getting reflected from a rigid boundary the wave suffers an additional phase change of\[\pi \] \[\Rightarrow \]\[y=0.8\,A\,\sin (\omega t+kx+\pi )\] \[\Rightarrow \]\[y=-0.8\,A\,\sin (\omega t+kx)\]


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