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MGIMS WARDHA MGIMS WARDHA Solved Paper-2010

  • question_answer
    A 1 kg stone at the end of 1 m long string is whirled in a vertical circle at constant speed of 4 m/s. The tension in the string is 6 N, when the stone is at

    A)  top of the circle              

    B)  bottom of the circle

    C)  half way down

    D)  None of the above

    Correct Answer: A

    Solution :

                     \[mg=1\times 10=10N\] \[\frac{m{{v}^{2}}}{r}=\frac{1\times {{(4)}^{2}}}{1}=16\] Tension at the top of circle \[=\frac{m{{v}^{2}}}{r}-mg=6N\] Tension at the bottom of circle \[=\frac{m{{v}^{2}}}{r}+mg=26N\]


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