A) 1.99V
B) 3.5 V
C) 5V
D) 6V
Correct Answer: A
Solution :
From Ohm's law \[i=\frac{E}{R+r}=\frac{2}{998+2}\] \[=2\times {{10}^{-3}}A\] \[R=988\,\Omega \] Potential difference across the voltmeter is \[V=iR=(2\times {{10}^{-3}})\times 998=1.996\,V\]You need to login to perform this action.
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