A) \[Al\]
B) \[A{{l}^{+}}\]
C) \[A{{l}^{2+}}\]
D) \[A{{l}^{3+}}\]
Correct Answer: A
Solution :
Atomic radii varies inversely with nuclear charge, ie, \[Atomic\text{ }radii\propto \frac{1}{nuclear\text{ }ch\arg e}\] Hence, Al shows the largest atomic radii.
You need to login to perform this action.
You will be redirected in
3 sec
