A) 0.25
B) 2.5
C) 0.502
D) 5.03
Correct Answer: C
Solution :
Mole fraction of\[{{H}_{2}}O\] \[=\frac{number\text{ }of\text{ }moles\text{ }of}{total\text{ }number\text{ }of\text{ }moles\text{ }of\text{ }all\text{ }components}\] Let the total mass of solution\[=100\text{ }g\] Mass of \[{{H}_{2}}O=25g\] Mass of \[{{C}_{2}}{{H}_{5}}OH=25g\] Mass of \[C{{H}_{3}}COOH=50\text{ }g\] Moles of\[{{H}_{2}}O=\frac{25}{18}=1.388\] (\[\because \]Molar mass of\[{{H}_{2}}O=18\]) Moles of \[{{C}_{2}}{{H}_{5}}OH=\frac{25}{46}=0.543\] (\[\because \]Molar mass\[{{C}_{2}}{{H}_{5}}OH=46\]) Moles of\[C{{H}_{3}}COOH=\frac{50}{60}=0.833\] (\[\because \]Molar mass of\[C{{H}_{3}}COOH=60\]) Total no. of moles\[=1.388+0.543+0.833\] \[=2.764\] \[\therefore \]Mole fraction of\[{{H}_{2}}O=\frac{1.388}{2.764}\] \[=0.502\]
You need to login to perform this action.
You will be redirected in
3 sec
