A) 10\[I\] and zero
B) 10\[I\] and 8\[I\]
C) 10\[I\]and 4 \[I\]
D) 16\[I\]and 4\[I\]
Correct Answer: D
Solution :
The ratio of maximum to minimum intensities is \[\frac{{{I}_{\max }}}{{{I}_{\min }}}=\frac{{{(\sqrt{{{I}_{1}}}+\sqrt{{{I}_{2}}})}^{2}}}{{{(\sqrt{{{I}_{1}}}-\sqrt{{{I}_{2}}})}^{2}}}\] \[=\frac{{{(1+3)}^{2}}}{{{(1-3)}^{2}}}=\frac{{{4}^{2}}}{{{2}^{2}}}\] \[=\frac{16}{4}\]
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