A) at. no. 84 and mass no. 214
B) at no. 82 and mass no. 214
C) at. no. 84 and mass no. 218
D) at. no. 82 and mass no. 218
Correct Answer: A
Solution :
Let element is 'A'. \[_{84}{{A}^{218}}{{\xrightarrow{\alpha -particle}}_{82}}{{B}^{214}}{{\xrightarrow{-\beta }}_{83}}{{C}^{214}}\] \[{{\xrightarrow{-\beta }}_{84}}{{D}^{214}}\] Hence, the resulting element will have at. no. 84 and mass no. 214.
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