A) \[25\times {{10}^{-}}^{3}mH\]
B) \[25mH\]
C) \[50\times {{10}^{-}}^{3}H\]
D) \[50\times {{10}^{-}}^{3}mH\]
Correct Answer: B
Solution :
Self-inductance of circular coil is \[L=\frac{{{\mu }_{0}}{{n}^{2}}\pi r}{2}\] \[=\frac{4\pi \times {{10}^{-7}}}{2}\times {{(500)}^{2}}\times \pi (5\times {{10}^{-2}})\] \[=25\times {{10}^{-3}}H\] \[=25mH\]
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