A) 273°C
B) 273 K
C) 546°C
D) 844 K
Correct Answer: A
Solution :
\[{{v}_{rms}}=\sqrt{\frac{3RT}{M}}\]rms velocity of He and\[{{H}_{2}}\]is same. i.e., \[\frac{{{T}_{{{H}_{2}}}}}{{{M}_{{{H}_{2}}}}}=\frac{{{T}_{He}}}{{{M}_{He}}}\] or \[\frac{273}{2}=\frac{{{T}_{He}}}{4}\] or \[\frac{273}{2}=\frac{{{T}_{He}}}{4}\] \[=546-273\] \[=273{}^\circ C\]You need to login to perform this action.
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