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MGIMS WARDHA MGIMS WARDHA Solved Paper-2011

  • question_answer
    The electric potential V is given as a function of distance \[x\] (m) by \[V=({{5.}^{2}}+10x-9)\]volt. Value of electric field at \[x\] = 1 m is

    A)  20V/m                                

    B)  6V/m

    C)  11 V/m                               

    D)  -23V/m

    Correct Answer: A

    Solution :

                     Voltage\[V=5{{x}^{2}}+10x-9\] Electric field\[E=-\frac{dV}{dx}=-\frac{d}{dx}(5{{x}^{2}}+10x-9)\] \[=-(10x-10)\] At \[x=1\text{ }m\] \[\therefore \]  \[E=10(1)+10=20\,V/m\]


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