A) 25 N
B) 5N
C) 2.5 N
D) 0.5 N
Correct Answer: D
Solution :
Maximum force \[F=m{{\omega }^{2}}a\] \[=m{{\left( \frac{2\pi }{T} \right)}^{2}}a=\frac{4{{\pi }^{2}}}{{{T}^{2}}}ma\] \[=\frac{4{{\pi }^{2}}}{{{\left( \frac{\pi }{5} \right)}^{2}}}\times \frac{10}{1000}\times 0.5\] \[=0.5\text{ }N\]
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