A) 1000 g
B) 1100g
C) 1200 g
D) 1252 g
Correct Answer: D
Solution :
The velocity attained by particle on falling from height\[2m\]. \[v=\sqrt{2gh}=\sqrt{2\times g\times 2}=2\sqrt{g}\] Rate of change of momentum of 100 particles \[=2mv\times 100=200\text{ }mv\] From Newton's law, rate of change of momentum is equal to force. Force\[=200\text{ }mv\] \[=200\times 1\times {{10}^{-3}}\times 2\sqrt{g}\] \[=1252g\] (reading).You need to login to perform this action.
You will be redirected in
3 sec