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MGIMS WARDHA MGIMS WARDHA Solved Paper-2011

  • question_answer
    A water film is made between two 10 cm long straight wires and at a distance of 0.5 cm. If distance between the wires is increased by 1 mm, then work done will be\[(T=7.2\times {{10}^{-2}}\,N/m)\]

    A)  \[7.22\times {{10}^{-5}}J\]         

    B)  \[1.44\times {{10}^{-5}}J\]

    C)   \[2.88\times {{10}^{-5}}J\]                        

    D)  \[5.76\times {{10}^{-5}}J\]

    Correct Answer: B

    Solution :

                     Work done\[W=2\Delta AT\] \[=2\times \frac{10}{100}\times \frac{1}{1000}\times 7.2\times {{10}^{-2}}\] \[=1.44\times {{10}^{-5}}J\]


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