A) \[0.186\times {{10}^{-20}}J\]
B) \[0.372\times {{10}^{-20}}J\]
C) \[0.56\times {{10}^{-20}}J\]
D) \[5.6\times {{10}^{-20}}J\]
Correct Answer: C
Solution :
Average kinetic energy\[=\frac{3}{2}kT\] T is absolute temperature\[=273\text{ }K\] \[KE=\frac{3}{2}\times 1.38\times {{10}^{-23}}\times 273\] \[KE=0.56\times {{10}^{-20}}J\]
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