A) 1 cm
B) 2 cm
C) 3 cm
D) 4 cm
Correct Answer: A
Solution :
Let initial velocity of body at point A is v. AB is 3 cm \[{{v}^{2}}={{u}^{2}}-2as\] \[{{\left( \frac{v}{2} \right)}^{2}}={{v}^{2}}-2a\times 3\] \[a=\frac{{{v}^{2}}}{8}\] Let an penetrating 3 cm in a wooden block the body moves\[x\]distance from B to C According to the question \[u=\frac{v}{2}\]and\[v=0\] \[\therefore \] \[{{(0)}^{2}}={{\left( \frac{v}{2} \right)}^{2}}-2\times \frac{{{v}^{2}}}{8}\times x\]
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