A) \[1.5\times {{10}^{9}}\]
B) \[4.62\times {{10}^{8}}\]
C) \[6.67\times {{10}^{8}}\]
D) \[10.35\times {{10}^{8}}\]
Correct Answer: C
Solution :
Average age, \[T=\frac{1}{\lambda }=\frac{1}{1.5\times {{10}^{-9}}}\] \[=6.67\times {{10}^{8}}s\]You need to login to perform this action.
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