MGIMS WARDHA MGIMS WARDHA Solved Paper-2011

  • question_answer
    The \[{{k}_{\alpha }}\] line from molybdenum (atomic number =42) has a wavelength of 0.7078 \[\overset{o}{\mathop{\text{A}}}\,\]. The wavelength of \[{{k}_{\alpha }}\] line of zinc (atomic number = 30) will be

    A) 1\[\overset{o}{\mathop{\text{A}}}\,\]                                

    B) 1.3872\[\overset{o}{\mathop{\text{A}}}\,\]

    C) 0.3541\[\overset{o}{\mathop{\text{A}}}\,\]                 

    D) 0.5\[\overset{o}{\mathop{\text{A}}}\,\]

    Correct Answer: B

    Solution :

    \[E\propto \frac{{{z}^{2}}}{{{n}^{2}}}\]and\[E\propto \frac{1}{\lambda }\] \[\therefore \]  \[\frac{{{Z}^{2}}}{{{n}^{2}}}=\frac{1}{\lambda }\]                                 \[\frac{Z_{1}^{2}}{Z_{2}^{2}}=\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}\]                                 \[\frac{{{(42)}^{2}}}{{{(30)}^{2}}}=\frac{{{\lambda }^{2}}}{0.7080}\]                                 \[{{\lambda }_{2}}=1.3872{AA}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner