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MGIMS WARDHA MGIMS WARDHA Solved Paper-2011

  • question_answer
    A steady current of 5 A is maintained for 45 min. During this time it deposits 4.572 g of zinc at the cathode of a voltmeter. ECE of zinc is

    A)  \[3.387\times {{10}^{-4}}\,g/C\]              

    B)  \[3.397\times {{10}^{-4}}\,g/C\]

    C)   \[3.384\times {{10}^{-3}}\,g/C\]             

    D)  \[3.394\times {{10}^{-3}}\,g/C\]

    Correct Answer: B

    Solution :

                     According to Faraday's law \[m=zit\]where z is electrochemical equivalent. \[\Rightarrow \]               \[a=\frac{m}{it}=\frac{4.572}{5\times 45\times 60}\] \[z=3.387\times {{10}^{-4}}g/C.\]


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