A) position isomers
B) chain isomers
C) functional isomers
D) optical isomers
Correct Answer: C
Solution :
\[\begin{matrix} \underset{\begin{smallmatrix} methoxy\text{ }methane \\ \,\,\,\,\,\,\,\,\,(ether) \\ \,\,\,\,\,\,\,({{C}_{2}}{{H}_{6}}O) \end{smallmatrix}}{\mathop{C{{H}_{3}}OC{{H}_{3}},}}\, & \underset{\begin{align} & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,ethanol \\ & (alcohol)\text{ }functional\text{ }group \\ & \,\,\,\,\,\,\,\,\,\,({{C}_{2}}{{H}_{5}}O)molecular \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,formula \\ \end{align}}{\mathop{{{C}_{2}}{{H}_{5}}OH}}\, \\ \end{matrix}\] Methoxy methane and ethanol both have same molecular formula but different functional groups so they are functional isomers.
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