A) \[\Delta E+2RT\]
B) \[\Delta F-2RT\]
C) \[\Delta F+RT\]
D) \[\Delta E-RT\]
Correct Answer: B
Solution :
\[{{N}_{2}}+3{{H}_{2}}2N{{H}_{3}}\] \[\Delta H=\Delta E+\Delta {{n}_{g}}RT\] \[\Delta {{n}_{g}}={{n}_{p}}-{{n}_{r}}=2-4=-2\] \[\therefore \] \[\Delta H=\Delta E+(-2)RT\] \[\Delta H=\Delta E-2RT\]
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