A) 60
B) 30
C) 15
D) 25
Correct Answer: B
Solution :
Using the relation \[\frac{m{{v}^{2}}}{r}=\mu R,R=mg\] \[\frac{m{{v}^{2}}}{r}=\mu mg\]or \[{{v}^{2}}=\mu rg\] \[{{v}^{2}}=0.6\times 150\times 10\] \[v=30\text{ }m/s\]You need to login to perform this action.
You will be redirected in
3 sec