question_answer

Equivalent capacity between A and B is

A)  \[2\mu F\]                                        

B)  \[3\mu F\]

C)  \[4\mu F\]                                        

D)  \[0.5\mu F\]

Correct Answer: D

Solution :

                Equivalent capacity of \[1\mu F\]and\[1\mu F\]capacitor joined in parallel \[C=1+1=2\mu F\] Now, this circuit can be represented as Now, the total capacity of circuit in series                 \[\frac{1}{C}=\frac{1}{2}+\frac{1}{1}+\frac{1}{2}\]                 \[C=\frac{1}{2}=0.5\,\mu F\]