A) 200 Hz
B) 400 Hz
C) 500 Hz
D) 600 Hz
Correct Answer: A
Solution :
Equation of wave is \[=a\sin \left( 400\pi t-\frac{\pi x}{0.85} \right)\] Comparing this equation with \[y=a\sin \left( \omega t-\frac{2\pi x}{\lambda } \right)\] \[\omega =400\pi \] \[\therefore \] \[2\pi n=400\pi \] \[n=200\text{ }Hz\]You need to login to perform this action.
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