A) 1,2,3-propane tri-ol
B) 3-hydroxy butanoic acid
C) 1,2-ethane di-ol
D) 3-methyl butanol-1
Correct Answer: A
Solution :
\[\underset{1,2,3-propane\text{ }triol}{\mathop{\overset{\begin{smallmatrix} OH \\ | \end{smallmatrix}}{\mathop{C{{H}_{2}}}}\,-\overset{\begin{smallmatrix} OH \\ | \end{smallmatrix}}{\mathop{C{{H}_{2}}}}\,-\overset{\begin{smallmatrix} OH \\ | \end{smallmatrix}}{\mathop{C{{H}_{2}}}}\,}}\,\]You need to login to perform this action.
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