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MGIMS WARDHA MGIMS WARDHA Solved Paper-2012

  • question_answer
    For a triode valve\[\mu =50,\Delta {{V}_{g}}=0.2V,\]then value of\[\Delta {{V}_{p}}\]is

    A)  5V                                         

    B)  10V

    C)  0.2V                                     

    D)  50V

    Correct Answer: B

    Solution :

                    Amplification factor \[\mu =\frac{\Delta {{V}_{p}}}{\Delta {{V}_{g}}}\] \[50=\frac{\Delta {{V}_{p}}}{0.2}\] \[\Delta {{V}_{P}}=10\,V\]


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