A) 42.91 g
B) 57.59 g
C) 13.69g
D) 36.38 g
Correct Answer: B
Solution :
Only pure Ag from the anode is oxidised, which in turn is deposited at cathode. By Faradays first law, weight of Ag deposited at cathode, \[W=Zit\] \[=\frac{108\times 5\times 2\times 3600}{1\times 96500}=40.29\,g\] but anode is 95% pure w.r.t., Ag. Hence, actual loss is \[=40.29\times \frac{100}{95}=42.41\text{ }g\] Weight of Ag-anode after electrolysis \[=100-42.41=57.59\text{ }g\]You need to login to perform this action.
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