A) lonisation energy of\[{{X}^{-}}(g)\] is y
B) Electron affinity of\[X(g)\]is\[x\]
C) Electron affinity of\[X(g)\]is\[-y\]
D) All of the above
Correct Answer: D
Solution :
\[X(g)+{{e}^{-}}\xrightarrow[{}]{{}}{{X}^{-}}(g);\Delta H=x=EA\]of \[X(g)\] \[{{X}^{-}}(g)\xrightarrow[{}]{{}}X(g)+{{e}^{-}};\Delta H=y=IE\]of\[{{X}^{-}}(g)\] \[=-EA\]of\[X(g)\] Therefore, all options are correct.You need to login to perform this action.
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