A) \[L/3\]
B) \[2L\]
C) \[4L\]
D) \[8L\]
Correct Answer: A
Solution :
The location of a point on the\[x-\]axis, at which the net electric field due to these two point charges is zero, from \[+{{q}_{1}},\]charge is\[=\frac{L}{1+\sqrt{\frac{{{q}_{2}}}{{{q}_{1}}}}}=\frac{L}{1+\sqrt{\frac{4q}{q}}}=\frac{L}{3}\]You need to login to perform this action.
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