A) chloroform
B) chloral
C) methyl chloride
D) monochloroacetic acid
Correct Answer: B
Solution :
Molecular formula of \[A={{C}_{2}}C{{l}_{3}}OH\] As reduces Fehtings solution and on oxidation gives a monocarboxylic acid (S). It means must be an aldehyde, i.e., \[\underset{(A)}{\mathop{CC{{l}_{3}}CHO}}\,\]. This is further confirmed by the reaction. \[{{C}_{2}}{{H}_{5}}OH+C{{l}_{2}}\xrightarrow[Oxidation]{[O]}C{{H}_{3}}CHO\] \[\xrightarrow[Chlorination]{C{{l}_{2}}}CC{{l}_{3}}CHO\] A = Chloral \[[CC{{l}_{3}}CHO]\]You need to login to perform this action.
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