A) butanol
B) aldol
C) ketol
D) acetal
Correct Answer: B
Solution :
\[\underset{Acetic\text{ }acid}{\mathop{C{{H}_{3}}COOH}}\,\xrightarrow[{}]{LiAl{{H}_{4}}}\underset{(X)}{\mathop{C{{H}_{3}}C{{H}_{2}}CH}}\,\xrightarrow[300{}^\circ C]{Cu}\] \[C{{H}_{3}}CHO\xrightarrow[{}]{\begin{smallmatrix} Dil.NaOH\text{ }aldol \\ \,\,\,condensatlon \end{smallmatrix}}\underset{(Z)\,Aldol}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{2}}CHO}}\,\]You need to login to perform this action.
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