A) 5 mol
B) 8 mol
C) 16 mol
D) 4 mol
Correct Answer: D
Solution :
As from reaction; \[A+2B\xrightarrow{{}}C\] It is clear that 1 mote of reacts with 2 mole of B to from 1 mole of C. \[\therefore \] 4 mole of A will react with\[2\times 4=8\] mole of B to from 4 mole of C. Here, B is limiting reagent. 1 mole of A remains unreacted.You need to login to perform this action.
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