A) \[pS{{O}_{2}}>p{{H}_{2}}>pC{{H}_{4}}\]
B) \[pS{{O}_{2}}>pC{{H}_{4}}>p{{H}_{2}}\]
C) \[p{{H}_{2}}>pS{{O}_{2}}>pC{{H}_{4}}\]
D) \[p{{H}_{2}}>pC{{H}_{4}}>pS{{O}_{2}}\]
Correct Answer: B
Solution :
Rate of diffusion \[\propto \frac{1}{\sqrt{molecular\text{ }mass}}\] \[\therefore \]Order of diffusion \[{{H}_{2}}>C{{H}_{4}}>S{{O}_{2}}\] and amount left is in the order: \[S{{O}_{2}}>C{{H}_{4}}>{{H}_{2}}\] Hence, order of partial pressure is \[pS{{O}_{2}}>pC{{H}_{4}}>p{{H}_{2}}\]You need to login to perform this action.
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