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MGIMS WARDHA MGIMS WARDHA Solved Paper-2014

  • question_answer
    Current in a circuit falls steadily from 2.0 A to 0.0 A in 10 ms. If an average emf of 200 V is induced, then the self-inductance of the circuit is

    A)  1 H                                        

    B)  2H

    C)  1/2H                                    

    D)  2H     

    Correct Answer: A

    Solution :

                    The relationship is given by \[\varepsilon =-L\frac{dI}{dt}\] \[200=\frac{2}{10\times {{10}^{-3}}}L\] \[L=1H\]


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