A) 4cm
B) 3cm
C) 2.18 cm
D) 2.05 cm
E) None of these above
Correct Answer: E
Solution :
The relationship between refractive index u. real depth and apparent depth is \[\mu =\frac{Real\text{ }depth}{Apparent\text{ }depth}=\frac{12.4\,cm}{9.3\,cm}=\frac{4}{3}\] For another liquid, \[\mu =1.6\] \[\mu =\frac{Real\text{ }depth}{Apparent\text{ }depth}\] Or \[1.6=\frac{12.4\,cm}{Apparent\text{ }depth}\] Apparent depth\[=\frac{12.4}{1.6}\] \[=7.75cm\] Distance moved by microscope \[=9.3-7.75=1.55\text{ }cm\]You need to login to perform this action.
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